Medium

Number of Perfect PairsPython

Full explanation · Time O(nlogn) · Space O(1)

# Time:  O(nlogn)
# Space: O(1)

# sort, two pointers, math
class Solution(object):
    def perfectPairs(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        for i in xrange(len(nums)):
            nums[i] = abs(nums[i])
        nums.sort()
        result = left = 0
        for right in xrange(len(nums)):
            while not (nums[right]-nums[left] <= nums[left]):
                left += 1
            result += (right-left+1)-1
        return result