Number of Orders in the Backlog — Python

# Time:  O(nlogn)
# Space: O(n)

import heapq


class Solution(object):
    def getNumberOfBacklogOrders(self, orders):
        """
        :type orders: List[List[int]]
        :rtype: int
        """
        MOD = 10**9 + 7
        buy, sell  = [], []  # max_heap, min_heap
        for p, a, t in orders:
            if t == 0:
                heapq.heappush(buy, [-p, a])
            else:
                heapq.heappush(sell, [p, a])
            while sell and buy and sell[0][0] <= -buy[0][0]:
                k = min(buy[0][1], sell[0][1])
                tmp = heapq.heappop(buy)
                tmp[1] -= k
                if tmp[1]:
                    heapq.heappush(buy, tmp)
                tmp = heapq.heappop(sell)
                tmp[1] -= k
                if tmp[1]:
                    heapq.heappush(sell, tmp)
        return reduce(lambda x, y: (x+y) % MOD, (a for _, a in buy + sell))