Easy
Number of Equivalent Domino Pairs — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
import collections
class Solution(object):
def numEquivDominoPairs(self, dominoes):
"""
:type dominoes: List[List[int]]
:rtype: int
"""
counter = collections.Counter((min(x), max(x)) for x in dominoes)
return sum(v*(v-1)//2 for v in counter.itervalues())