Medium
Number of Centered Subarrays — C++
Full explanation · Time O(n^2) · Space O(n)
// Time: O(n^2)
// Space: O(n)
// hash table
class Solution {
public:
int centeredSubarrays(vector<int>& nums) {
int result = 0;
for (int i = 0; i < size(nums); ++i) {
unordered_set<int> lookup;
for (int j = i, total = 0; j < size(nums); ++j) {
lookup.emplace(nums[j]);
total += nums[j];
if (lookup.count(total)) {
++result;
}
}
}
return result;
}
};