Easy

Number of Beautiful PairsPython

Full explanation · Time O(nlogr) · Space O(1)

# Time:  O(nlogr)
# Space: O(1)

# number theory, freq table
class Solution(object):
    def countBeautifulPairs(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        def gcd(a, b):
            while b:
                a, b = b, a%b
            return a

        result = 0
        cnt = [0]*10
        for x in nums:
            for i in xrange(1, 10):
                if gcd(i, x%10) == 1:
                    result += cnt[i]
            while x >= 10:
                x //= 10
            cnt[x] += 1
        return result