Medium

Non-overlapping IntervalsC++

Full explanation · Time O(nlogn) · Space O(1)

// Time:  O(nlogn)
// Space: O(1)

class Solution {
public:
    int eraseOverlapIntervals(vector<vector<int>>& intervals) {
        sort(intervals.begin(), intervals.end(), [](const auto& a, const auto& b) { return a[1] < b[1]; });
        int result = 0, right = numeric_limits<int>::min();
        for (const auto& x : intervals) {
            if (x[0] < right) {
                ++result;
            } else {
                right = x[1];
            }
        }
        return result;
    }
};

// Time:  O(nlogn)
// Space: O(1)
class Solution2 {
public:
    int eraseOverlapIntervals(vector<vector<int>>& intervals) {
        sort(intervals.begin(), intervals.end(), [](const auto& a, const auto& b) { return a[0] < b[0]; });
        int result = 0, prev = 0;
        for (int i = 1; i < intervals.size(); ++i) {
            if (intervals[i][0] < intervals[prev][1]) {
                if (intervals[i][1] < intervals[prev][1]) {
                    prev = i;
                }
                ++result;
            } else {
                prev = i;
            }
        }
        return result;
    }
};