Medium
Non-overlapping Intervals — C++
Full explanation · Time O(nlogn) · Space O(1)
// Time: O(nlogn)
// Space: O(1)
class Solution {
public:
int eraseOverlapIntervals(vector<vector<int>>& intervals) {
sort(intervals.begin(), intervals.end(), [](const auto& a, const auto& b) { return a[1] < b[1]; });
int result = 0, right = numeric_limits<int>::min();
for (const auto& x : intervals) {
if (x[0] < right) {
++result;
} else {
right = x[1];
}
}
return result;
}
};
// Time: O(nlogn)
// Space: O(1)
class Solution2 {
public:
int eraseOverlapIntervals(vector<vector<int>>& intervals) {
sort(intervals.begin(), intervals.end(), [](const auto& a, const auto& b) { return a[0] < b[0]; });
int result = 0, prev = 0;
for (int i = 1; i < intervals.size(); ++i) {
if (intervals[i][0] < intervals[prev][1]) {
if (intervals[i][1] < intervals[prev][1]) {
prev = i;
}
++result;
} else {
prev = i;
}
}
return result;
}
};