Medium
Most Frequent Subtree Sum — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> findFrequentTreeSum(TreeNode* root) {
unordered_map<int,int> counts;
int max_count = 0;
countSubtreeSumsHelper(root, &counts, &max_count);
vector<int> result;
for (const auto& kvp : counts){
if (kvp.second == max_count) {
result.emplace_back(kvp.first);
}
}
return result;
}
private:
int countSubtreeSumsHelper(TreeNode *root, unordered_map<int,int> *counts, int *max_count) {
if (!root) {
return 0;
}
auto sum = root->val +
countSubtreeSumsHelper(root->left, counts, max_count) +
countSubtreeSumsHelper(root->right, counts, max_count);
++(*counts)[sum];
(*max_count) = max((*max_count), (*counts)[sum]);
return sum;
}
};