Easy

Monotonic ArrayPython

Full explanation · Time O(n) · Space O(1)

# Time:  O(n)
# Space: O(1)

class Solution(object):
    def isMonotonic(self, A):
        """
        :type A: List[int]
        :rtype: bool
        """
        inc, dec = False, False
        for i in xrange(len(A)-1):
            if A[i] < A[i+1]:
                inc = True
            elif A[i] > A[i+1]:
                dec = True
        return not inc or not dec