Medium
Minimum XOR Path in a Grid — C++
Full explanation · Time O(m * n * r) · Space O(n * r)
// Time: O(m * n * r), r = max(x for row in grid for x in row)
// Space: O(n * r / 64)
// dp, bitset
class Solution {
public:
int minCost(vector<vector<int>>& grid) {
static const int MAX_LEN = 1024;
vector<bitset<MAX_LEN>> dp(size(grid[0]));
dp[0].set(0);
for (int i = 0; i < size(grid); ++i) {
vector<bitset<MAX_LEN>> new_dp(size(grid[0]));
for (int j = 0; j < size(grid[0]); ++j) {
for (int k = 0; k < MAX_LEN; ++k) {
if (dp[j][k] || (j - 1 >= 0 && new_dp[j - 1][k])) {
new_dp[j].set(k ^ grid[i][j]);
}
}
}
dp = move(new_dp);
}
for (int i = 0; i < MAX_LEN; ++i) {
if (dp.back()[i]) {
return i;
}
}
return -1;
}
};
// Time: O(m * n * r), r = max(x for row in grid for x in row)
// Space: O(n * r)
// dp
class Solution2 {
public:
int minCost(vector<vector<int>>& grid) {
uint32_t mx = 0;
for (const auto& row : grid) {
mx = max(mx, static_cast<uint32_t>(ranges::max(row)));
}
const auto& l = 1 << bit_width(mx);
vector<vector<bool>> dp(size(grid[0]), vector<bool>(l));
dp[0][0] = true;
for (int i = 0; i < size(grid); ++i) {
vector<vector<bool>> new_dp(size(grid[0]), vector<bool>(l));
for (int j = 0; j < size(grid[0]); ++j) {
for (int k = 0; k < l; ++k) {
if (dp[j][k] || (j - 1 >= 0 && new_dp[j - 1][k])) {
new_dp[j][k ^ grid[i][j]] = true;
}
}
}
dp = move(new_dp);
}
for (int i = 0; i < l; ++i) {
if (dp.back()[i]) {
return i;
}
}
return -1;
}
};
// Time: O(m * n * r), r = max(x for row in grid for x in row)
// Space: O(n * r)
// dp
class Solution_TLE {
public:
int minCost(vector<vector<int>>& grid) {
vector<unordered_set<int>> dp(size(grid[0]));
dp[0].emplace(0);
for (int i = 0; i < size(grid); ++i) {
vector<unordered_set<int>> new_dp(size(grid[0]));
for (int j = 0; j < size(grid[0]); ++j) {
for (const auto& k : dp[j]) {
new_dp[j].emplace(k ^ grid[i][j]);
}
if (j - 1 < 0) {
continue;
}
for (const auto& k : new_dp[j - 1]) {
new_dp[j].emplace(k ^ grid[i][j]);
}
}
dp = move(new_dp);
}
return ranges::min(dp.back());
}
};