Hard
Minimum Time to Revert Word to Initial State II — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// z-function
class Solution {
public:
int minimumTimeToInitialState(string word, int k) {
const auto& ceil_divide = [](int a, int b) {
return (a + b - 1) / b;
};
// Template: https://cp-algorithms.com/string/z-function.html
const auto& z_function = [](const string& s) { // Time: O(n), Space: O(n)
vector<int> z(size(s));
for (int i = 1, l = 0, r = 0; i < size(z); ++i) {
if (i <= r) {
z[i] = min(r - i + 1, z[i - l]);
}
while (i + z[i] < size(z) && s[z[i]] == s[i + z[i]]) {
++z[i];
}
if (i + z[i] - 1 > r) {
l = i, r = i + z[i] - 1;
}
}
return z;
};
const auto& z = z_function(word);
for (int i = k; i < size(word); i += k) {
if (z[i] == size(word) - i) {
return i / k;
}
}
return ceil_divide(size(word), k);
}
};