Easy
Minimum Sum of Mountain Triplets I — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// prefix sum
class Solution {
public:
int minimumSum(vector<int>& nums) {
static const int INF = numeric_limits<int>::max();
vector<int> right(size(nums), INF);
for (int i = size(nums) - 1, curr = INF; i >= 0; --i) {
right[i] = curr;
curr = min(curr, nums[i]);
}
int result = INF;
for (int i = 0, curr = INF; i < size(nums); ++i) {
if (curr < nums[i] && nums[i] > right[i]) {
result = min(result, curr + nums[i] + right[i]);
}
curr = min(curr, nums[i]);
}
return result != INF ? result : -1;
}
};
// Time: O(n)
// Space: O(n)
// prefix sum
class Solution2 {
public:
int minimumSum(vector<int>& nums) {
static const int INF = numeric_limits<int>::max();
vector<int> left(size(nums), INF);
for (int i = 0, curr = INF; i < size(nums); ++i) {
left[i] = curr;
curr = min(curr, nums[i]);
}
vector<int> right(size(nums), INF);
for (int i = size(nums) - 1, curr = INF; i >= 0; --i) {
right[i] = curr;
curr = min(curr, nums[i]);
}
int result = INF;
for (int i = 0; i < size(nums); ++i) {
if (left[i] < nums[i] && nums[i] > right[i]) {
result = min(result, left[i] + nums[i] + right[i]);
}
}
return result != INF ? result : -1;
}
};