Hard
Minimum Replacements to Sort the Array — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# greedy, math
class Solution(object):
def minimumReplacement(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
def ceil_divide(a, b):
return (a+b-1)//b
result = 0
curr = nums[-1]
for x in reversed(nums):
cnt = ceil_divide(x, curr)
result += cnt-1
curr = x//cnt
return result