Medium
Minimum Path Cost in a Hidden Grid — Python
Full explanation · Time O(m * n * log(m * n)) · Space O(m * n)
# Time: O(m * n * log(m * n))
# Space: O(m * n)
class GridMaster(object):
def canMove(self, direction):
pass
def move(self, direction):
pass
def isTarget(self):
pass
import collections
import heapq
class Solution(object):
def findShortestPath(self, master):
"""
:type master: GridMaster
:rtype: int
"""
directions = {'L': (0, -1), 'R': (0, 1), 'U': (-1, 0), 'D': (1, 0)}
rollback = {'L': 'R', 'R': 'L', 'U': 'D', 'D': 'U'}
def dfs(pos, target, master, lookup, adj):
if target[0] is None and master.isTarget():
target[0] = pos
lookup.add(pos)
for d, (di, dj) in directions.iteritems():
if not master.canMove(d):
continue
nei = (pos[0]+di, pos[1]+dj)
if nei in adj[pos]:
continue
adj[pos][nei] = master.move(d)
if nei not in lookup:
dfs(nei, target, master, lookup, adj)
adj[nei][pos] = master.move(rollback[d])
def dijkstra(adj, start, target):
dist = {start:0}
min_heap = [(0, start)]
while min_heap:
curr, u = heapq.heappop(min_heap)
if dist[u] < curr:
continue
for v, w in adj[u].iteritems():
if v in dist and dist[v] <= curr+w:
continue
dist[v] = curr+w
heapq.heappush(min_heap, (curr+w, v))
return dist[target] if target in dist else -1
start = (0, 0)
target = [None]
adj = collections.defaultdict(dict)
dfs(start, target, master, set(), adj)
if not target[0]:
return -1
return dijkstra(adj, start, target[0])