Medium
Minimum Operations to Transform String — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
int minOperations(string s) {
int result = 0;
for (const auto& x : s) {
result = max(result, (26 - (x - 'a')) % 26);
}
return result;
}
};