Medium
Minimum Operations to Transform Binary String — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
int minOperations(string s1, string s2) {
if (s1 == "1" && s2 == "0") {
return -1;
}
int result = 0;
for (int i = 0; i < size(s1); ++i) {
if (s1[i] == s2[i]) {
continue;
}
if (s1[i] == '0') {
++result;
} else if (i + 1 < size(s1)) {
result += s1[i + 1] == '1' ? 1 : 2;
s1[i + 1] = '0';
} else {
result += 2;
}
}
return result;
}
};