Medium

Minimum Operations to Sort a PermutationC++

Full explanation · Time O(n) · Space O(1)

// Time:  O(n)
// Space: O(1)

// array
class Solution {
public:
    int minOperations(vector<int>& nums) {
        const auto& check = [&](int i, int d) {
            for (int j = 0; j < size(nums); ++j) {
                if (nums[((i + j * d) + size(nums)) % size(nums)] != j) {
                    return false;
                }
            }
            return true;
        };

        const auto& idx = distance(cbegin(nums), find(cbegin(nums), cend(nums), 0));
        if (check(idx, +1)) {
            return min(idx, 1 + (static_cast<int>(size(nums)) - idx) + 1);
        }
        if (check(idx, -1)) {
            return min((idx + 1) + 1, 1 + (static_cast<int>(size(nums)) - (idx + 1)));
        }
        return -1;
    }
};

// Time:  O(n)
// Space: O(1)
// array
class Solution2 {
public:
    int minOperations(vector<int>& nums) {
        const auto& check = [&](const auto& compare) {
            for (int i = 0, cnt = 0; i < size(nums); ++i) {
                if (compare(nums[i], nums[(i + 1) % size(nums)])) {
                    continue;
                }
                if (++cnt > 1) {
                    return false;
                }
            }
            return true;
        };

        const auto& idx = distance(cbegin(nums), find(cbegin(nums), cend(nums), 0));
        if (check([](const auto& a, const auto& b) { return a <= b; })) {
            return min(idx, 1 + (static_cast<int>(size(nums)) - idx) + 1);
        }
        if (check([](const auto& a, const auto& b) { return a >= b; })) {
            return min((idx + 1) + 1, 1 + (static_cast<int>(size(nums)) - (idx + 1)));
        }
        return -1;
    }
};