Medium
Minimum Operations to Make the Array Alternating — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// freq table
class Solution {
public:
int minimumOperations(vector<int>& nums) {
const auto& find_top1_and_top2 = [](const auto& cnt) {
int top1 = -1, top2 = -1;
for (const auto& [k, v] : cnt) {
if (top1 == -1 || v >= cnt.at(top1)) {
top2 = top1;
top1 = k;
} else if (top2 == -1 || v > cnt.at(top2)) {
top2 = k;
}
}
return make_pair(top1, top2);
};
unordered_map<int, int> even;
for (int i = 0; i < size(nums); i += 2) {
++even[nums[i]];
}
unordered_map<int, int> odd;
for (int i = 1; i < size(nums); i += 2) {
++odd[nums[i]];
}
const auto& [even_top1, even_top2] = find_top1_and_top2(even);
const auto& [odd_top1, odd_top2] = find_top1_and_top2(odd);
if (even_top1 != odd_top1) {
return size(nums) - even[even_top1] - (odd_top1 != -1 ? odd[odd_top1] : 0);
}
return min(size(nums) - even[even_top1] - (odd_top2 != -1 ? odd[odd_top2] : 0),
size(nums) - odd[odd_top1] - (even_top2 != -1 ? even[even_top2] : 0));
}
};