Medium
Minimum Operations to Make Array Non Decreasing — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
long long minOperations(vector<int>& nums) {
int64_t result = 0;
for (int i = 0; i + 1 < size(nums); ++i) {
result += max(nums[i] - nums[i + 1], 0);
}
return result;
}
};