Medium
Minimum Operations to Make Array Equal — Python
Full explanation · Time O(1) · Space O(1)
# Time: O(1)
# Space: O(1)
class Solution(object):
def minOperations(self, n):
"""
:type n: int
:rtype: int
"""
# total = sum(2i+1 for i in xrange(n)) = n^2
# left_half_total = sum(2i+1 for i in xrange(n//2)) = (n//2)^2
# result = (n//2) * (total//n) - left_half_total = (n//2)*(n-n//2) = (n//2)*((n+1)//2)
return (n//2)*((n+1)//2)