Medium
Minimum Operations to Make Array Equal — C++
Full explanation · Time O(1) · Space O(1)
// Time: O(1)
// Space: O(1)
class Solution {
public:
int minOperations(int n) {
// total = sum(2i+1 for i in xrange(n)) = n^2
// left_half_total = sum(2i+1 for i in xrange(n//2)) = (n//2)^2
// result = (n//2) * (total//n) - left_half_total = (n//2)*(n-n//2) = (n//2)*((n+1)//2)
return (n / 2) * ((n + 1) / 2);
}
};