Hard
Minimum Operations to Make a Subsequence — C++
Full explanation · Time O(nlogn) · Space O(n)
// Time: O(nlogn)
// Space: O(n)
class Solution {
public:
int minOperations(vector<int>& target, vector<int>& arr) {
unordered_map<int, int> lookup;
for (int i = 0; i < size(target); ++i) {
lookup[target[i]] = i;
}
vector<int> lis;
for (const auto& x : arr) {
if (!lookup.count(x)) {
continue;
}
auto it = lower_bound(begin(lis), end(lis), lookup[x]);
if (it == end(lis)) {
lis.emplace_back(lookup[x]);
} else {
*it = lookup[x];
}
}
return size(target) - size(lis);
}
};
// Time: O(nlogn)
// Space: O(n)
// segment tree solution
class Solution2 {
public:
int minOperations(vector<int>& target, vector<int>& arr) {
unordered_map<int, int> lookup;
for (int i = 0; i < size(target); ++i) {
lookup[target[i]] = i;
}
SegmentTree st(size(lookup));
for (const auto& x : arr) {
if (!lookup.count(x)) {
continue;
}
st.update(lookup[x], lookup[x], (lookup[x] >= 1) ? st.query(0, lookup[x] - 1) + 1 : 1);
}
return size(target) - ((size(lookup) >= 1) ? st.query(0, size(lookup) - 1) : 0);
}
private:
class SegmentTree {
public:
SegmentTree(int N)
: N_(N),
tree_(2 * N),
lazy_(N)
{
H_ = 1;
while ((1 << H_) < N) {
++H_;
}
}
void update(int L, int R, int h) {
L += N_; R += N_;
int L0 = L, R0 = R;
while (L <= R) {
if ((L & 1) == 1) {
apply(L++, h);
}
if ((R & 1) == 0) {
apply(R--, h);
}
L >>= 1; R >>= 1;
}
pull(L0); pull(R0);
}
int query(int L, int R) {
L += N_; R += N_;
auto result = 0;
push(L); push(R);
while (L <= R) {
if ((L & 1) == 1) {
result = max(result, tree_[L++]);
}
if ((R & 1) == 0) {
result = max(result, tree_[R--]);
}
L >>= 1; R >>= 1;
}
return result;
}
private:
int N_, H_;
vector<int> tree_, lazy_;
void apply(int x, int val) {
tree_[x] = max(tree_[x], val);
if (x < N_) {
lazy_[x] = max(lazy_[x], val);
}
}
void pull(int x) {
while (x > 1) {
x >>= 1;
tree_[x] = max(tree_[x * 2], tree_[x * 2 + 1]);
tree_[x] = max(tree_[x], lazy_[x]);
}
}
void push(int x) {
for (int h = H_; h > 0; --h) {
int y = x >> h;
if (lazy_[y] > 0) {
apply(y * 2, lazy_[y]);
apply(y * 2 + 1, lazy_[y]);
lazy_[y] = 0;
}
}
}
};
};