Medium
Minimum Number of Swaps to Make the String Balanced — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def minSwaps(self, s):
"""
:type s: str
:rtype: int
"""
result = curr = 0
for c in s:
if c == ']':
curr += 1
result = max(result, curr)
else:
curr -= 1
return (result+1)//2