Easy
Minimum Number of Pushes to Type Word I — C++
Full explanation · Time O(4) · Space O(1)
// Time: O(4)
// Space: O(1)
// greedy
class Solution {
public:
int minimumPushes(string word) {
const auto& ceil_divide = [](int a, int b) {
return (a + b - 1) / b;
};
int result = 0;
const int l = ceil_divide(size(word), (9 - 2 + 1));
for (int i = 0; i < l; ++i) {
result += (i + 1) * min(static_cast<int>(size(word)) - i * (9 - 2 + 1), (9 - 2 + 1));
}
return result;
}
};
// Time: O(26)
// Space: O(26)
// freq table, greedy
class Solution2 {
public:
int minimumPushes(string word) {
vector<int> cnt(26);
for (const auto& x : word) {
++cnt[x - 'a'];
}
sort(rbegin(cnt), rend(cnt));
int result = 0;
for (int i = 0; i < size(cnt); ++i) {
result += cnt[i] * (i / (9 - 2 + 1) + 1);
}
return result;
}
};