Hard
Minimum Number of Increments on Subarrays to Form a Target Array — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int minNumberOperations(vector<int>& target) {
int result = 0;
for (int i = 0; i <= size(target); ++i) {
result += max((i < size(target) ? target[i] : 0) - (i - 1 >= 0 ? target[i - 1] : 0), 0);
}
return result;
}
};