Medium
Minimum Number of Days to Make m Bouquets — Python
Full explanation · Time O(nlogd) · Space O(1)
# Time: O(nlogd), d is the max day of bloomDay
# Space: O(1)
class Solution(object):
def minDays(self, bloomDay, m, k):
"""
:type bloomDay: List[int]
:type m: int
:type k: int
:rtype: int
"""
def check(bloomDay, m, k, x):
result = count = 0
for d in bloomDay:
count = count+1 if d <= x else 0
if count == k:
count = 0
result += 1
if result == m:
break
return result >= m
if m*k > len(bloomDay):
return -1
left, right = 1, max(bloomDay)
while left <= right:
mid = left + (right-left)//2
if check(bloomDay, m, k, mid):
right = mid-1
else:
left = mid+1
return left