Easy
Minimum Moves to Equal Array Elements — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int minMoves(vector<int>& nums) {
return accumulate(nums.cbegin(), nums.cend(), 0) -
nums.size() * *min_element(nums.cbegin(), nums.cend());
}
};