Hard
Minimum Edge Toggles on a Tree — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
# greedy, topological sort, bitmasks
class Solution(object):
def minimumFlips(self, n, edges, start, target):
"""
:type n: int
:type edges: List[List[int]]
:type start: str
:type target: str
:rtype: List[int]
"""
diff = [1 if start[u] != target[u] else 0 for u in xrange(n)]
if sum(diff)%2:
return [-1]
degree = [0]*n
adj = [0]*n
edge = [0]*n
for idx, (u, v) in enumerate(edges):
degree[u] += 1
degree[v] += 1
adj[u] ^= v
adj[v] ^= u
edge[u] ^= idx
edge[v] ^= idx
lookup = [False]*len(edges)
for u in xrange(n):
while degree[u] == 1:
v, idx = adj[u], edge[u]
degree[u] -= 1
degree[v] -= 1
adj[u] ^= v
adj[v] ^= u
edge[u] ^= idx
edge[v] ^= idx
if diff[u]:
diff[u] ^= 1
diff[v] ^= 1
lookup[idx] = True
u = v
return [i for i in xrange(len(lookup)) if lookup[i]]
# Time: O(n)
# Space: O(n)
# greedy, topological sort
class Solution2(object):
def minimumFlips(self, n, edges, start, target):
"""
:type n: int
:type edges: List[List[int]]
:type start: str
:type target: str
:rtype: List[int]
"""
def topological_sort():
lookup = [False]*len(adj)
q = [u for u in xrange(len(adj)) if degree[u] == 1]
while q:
new_q = []
for u in q:
for v, idx in adj[u]:
if degree[v] == 0:
continue
degree[u] -= 1
degree[v] -= 1
if degree[v] == 1:
new_q.append(v)
if diff[u]:
diff[u] ^= 1
diff[v] ^= 1
lookup[idx] = True
q = new_q
return lookup
diff = [1 if start[u] != target[u] else 0 for u in xrange(n)]
if sum(diff)%2:
return [-1]
degree = [0]*n
adj = [[] for _ in xrange(n)]
for idx, (u, v) in enumerate(edges):
degree[u] += 1
degree[v] += 1
adj[u].append((v, idx))
adj[v].append((u, idx))
lookup = topological_sort()
return [i for i in xrange(len(lookup)) if lookup[i]]