Medium
Minimum Division Operations to Make Array Non Decreasing — C++
Full explanation · Time precompute: O(r) runtime: O(n) · Space O(r)
// Time: precompute: O(r)
// runtime: O(n)
// Space: O(r)
// greedy, number theory
vector<int> linear_sieve_of_eratosthenes(int n) { // Time: O(n), Space: O(n)
vector<int> spf(n + 1, -1);
vector<int> primes;
for (int i = 2; i <= n; ++i) {
if (spf[i] == -1) {
spf[i] = i;
primes.emplace_back(i);
}
for (const auto& p : primes) {
if (i * p > n || p > spf[i]) {
break;
}
spf[i * p] = p;
}
}
return spf;
}
const int MAX_N = 1e6;
const auto& SPF = linear_sieve_of_eratosthenes(MAX_N);
class Solution {
public:
int minOperations(vector<int>& nums) {
int result = 0;
for (int i = size(nums) - 2; i >= 0; --i) {
if (nums[i] <= nums[i + 1]) {
continue;
}
if (SPF[nums[i]] > nums[i + 1]) {
return -1;
}
nums[i] = SPF[nums[i]];
++result;
}
return result;
}
};