Hard
Minimum Deletions to Make Array Divisible — Python
Full explanation · Time O(n + m + logr) · Space O(1)
# Time: O(n + m + logr), r is max(numsDivide)
# Space: O(1)
# gcd
class Solution(object):
def minOperations(self, nums, numsDivide):
"""
:type nums: List[int]
:type numsDivide: List[int]
:rtype: int
"""
def gcd(a, b): # Time: O(log(min(a, b)))
while b:
a, b = b, a%b
return a
g = reduce(gcd, numsDivide)
mn = float("inf")
for x in nums:
if g%x == 0:
mn = min(mn, x)
return sum(x < mn for x in nums) if mn != float("inf") else -1