Medium
Minimum Cost For Tickets — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// space: O(1)
class Solution {
public:
int mincostTickets(vector<int>& days, vector<int>& costs) {
static vector<int> durations{1, 7, 30};
const int W = durations.back();
vector<int> dp(W, numeric_limits<int>::max());
dp[0] = 0;
vector<int> last_buy_days{0, 0, 0};
for (int i = 1; i < days.size() + 1; ++i) {
dp[i % W] = numeric_limits<int>::max();
for (int j = 0; j < durations.size(); ++j) {
while (i - 1 < days.size() &&
days[i - 1] > days[last_buy_days[j]] + durations[j] - 1) {
++last_buy_days[j]; // Time: O(n)
}
dp[i % W] = min(dp[i % W], dp[last_buy_days[j] % W] + costs[j]);
}
}
return dp[days.size() % W];
}
};