Medium
Minimum Cost for Cutting Cake I — Python
Full explanation · Time O(mlogm + nlogn) · Space O(1)
# Time: O(mlogm + nlogn)
# Space: O(1)
# sort, greedy
class Solution(object):
def minimumCost(self, m, n, horizontalCut, verticalCut):
"""
:type m: int
:type n: int
:type horizontalCut: List[int]
:type verticalCut: List[int]
:rtype: int
"""
horizontalCut.sort()
verticalCut.sort()
result = 0
cnt_h = cnt_v = 1
while horizontalCut or verticalCut:
if not verticalCut or (horizontalCut and horizontalCut[-1] > verticalCut[-1]):
result += horizontalCut.pop()*cnt_h
cnt_v += 1
else:
result += verticalCut.pop()*cnt_v
cnt_h += 1
return result
# Time: O(mlogm + nlogn)
# Space: O(1)
# sort, greedy
class Solution2(object):
def minimumCost(self, m, n, horizontalCut, verticalCut):
"""
:type m: int
:type n: int
:type horizontalCut: List[int]
:type verticalCut: List[int]
:rtype: int
"""
horizontalCut.sort(reverse=True)
verticalCut.sort(reverse=True)
result = i = j = 0
while i < len(horizontalCut) or j < len(verticalCut):
if j == len(verticalCut) or (i < len(horizontalCut) and horizontalCut[i] > verticalCut[j]):
result += horizontalCut[i]*(j+1)
i += 1
else:
result += verticalCut[j]*(i+1)
j += 1
return result
# Time: O((m + n) * m^2 * n^2)
# Space: O(m^2 * n^2)
# memoization
class Solution3(object):
def minimumCost(self, m, n, horizontalCut, verticalCut):
"""
:type m: int
:type n: int
:type horizontalCut: List[int]
:type verticalCut: List[int]
:rtype: int
"""
def memoization(x1, y1, x2, y2):
if (x1, y1) == (x2, y2):
return 0
if lookup[x1][y1][x2][y2] == -1:
mn = float("inf")
for x in xrange(x1, x2):
mn = min(ret, memoization(x1, y1, x, y2)+memoization(x+1, y1, x2, y2)+horizontalCut[x])
for y in xrange(y1, y2):
mn = min(ret, memoization(x1, y1, x2, y)+memoization(x1, y+1, x2, y2)+verticalCut[y])
lookup[x1][y1][x2][y2] = mn
return lookup[x1][y1][x2][y2]
lookup = [[[[-1]*n for _ in range(m)]for _ in range(n)] for _ in range(m)]
return memoization(0, 0, m-1, n-1)