Medium
Minimum Consecutive Cards to Pick Up — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// hash table
class Solution {
public:
int minimumCardPickup(vector<int>& cards) {
static const int INF = numeric_limits<int>::max();
unordered_map<int, int> lookup;
int result = INF;
for (int i = 0; i < size(cards); ++i) {
if (lookup.count(cards[i])) {
result = min(result, i - lookup[cards[i]] + 1);
}
lookup[cards[i]] = i;
}
return result != INF ? result : -1;
}
};