Medium
Minimum ASCII Delete Sum for Two Strings — Python
Full explanation · Time O(m * n) · Space O(n)
# Time: O(m * n)
# Space: O(n)
class Solution(object):
def minimumDeleteSum(self, s1, s2):
"""
:type s1: str
:type s2: str
:rtype: int
"""
dp = [[0] * (len(s2)+1) for _ in xrange(2)]
for j in xrange(len(s2)):
dp[0][j+1] = dp[0][j] + ord(s2[j])
for i in xrange(len(s1)):
dp[(i+1)%2][0] = dp[i%2][0] + ord(s1[i])
for j in xrange(len(s2)):
if s1[i] == s2[j]:
dp[(i+1)%2][j+1] = dp[i%2][j]
else:
dp[(i+1)%2][j+1] = min(dp[i%2][j+1] + ord(s1[i]), \
dp[(i+1)%2][j] + ord(s2[j]))
return dp[len(s1)%2][-1]
# Time: O(m * n)
# Space: O(m * n)
class Solution2(object):
def minimumDeleteSum(self, s1, s2):
"""
:type s1: str
:type s2: str
:rtype: int
"""
dp = [[0] * (len(s2)+1) for _ in xrange(len(s1)+1)]
for i in xrange(len(s1)):
dp[i+1][0] = dp[i][0] + ord(s1[i])
for j in xrange(len(s2)):
dp[0][j+1] = dp[0][j] + ord(s2[j])
for i in xrange(len(s1)):
for j in xrange(len(s2)):
if s1[i] == s2[j]:
dp[i+1][j+1] = dp[i][j]
else:
dp[i+1][j+1] = min(dp[i][j+1] + ord(s1[i]), \
dp[i+1][j] + ord(s2[j]))
return dp[-1][-1]