Medium
Minimum Adjacent Swaps to Alternate Parity — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
// greedy
class Solution {
public:
int minSwaps(vector<int>& nums) {
const auto& count = [&](int j) {
int result = 0;
for (int i = 0; i < size(nums); ++i) {
if (nums[i] % 2) {
result += abs(j - i);
j += 2;
}
}
return result;
};
const auto& cnt = accumulate(cbegin(nums), cend(nums), 0, [](const auto& accu, const auto& x) {
return accu + x % 2;
});
if (cnt == size(nums) - cnt) {
return min(count(0), count(1));
}
if (cnt == (size(nums) - cnt) + 1) {
return count(0);
}
if (cnt + 1 == size(nums) - cnt) {
return count(1);
}
return -1;
}
};