Medium
Minimizing Array After Replacing Pairs With Their Product — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# greedy
class Solution(object):
def minArrayLength(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
if 0 in nums:
return 1
result = len(nums)
curr = nums[0]
for i in xrange(1, len(nums)):
if curr*nums[i] > k:
curr = nums[i]
else:
curr *= nums[i]
result -= 1
return result