Medium
Minimized Maximum of Products Distributed to Any Store — C++
Full explanation · Time O(nlogm) · Space O(1)
// Time: O(nlogm), m is the max of quantities
// Space: O(1)
class Solution {
public:
int minimizedMaximum(int n, vector<int>& quantities) {
int left = 1, right = *max_element(cbegin(quantities), cend(quantities));
while (left <= right) {
const auto& mid = left + (right - left) / 2;
if (check(n, quantities, mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return left;
}
private:
bool check(int n, const vector<int>& quantities, int x) {
return accumulate(cbegin(quantities), cend(quantities), 0,
[this, &x](const auto& total, const auto& q) {
return total + ceil_divide(q, x);
}) <= n;
}
int ceil_divide(int a, int b) {
return (a + (b - 1)) / b;
}
};