Medium
Maximum Total Importance of Roads — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
# greedy, counting sort
class Solution(object):
def maximumImportance(self, n, roads):
"""
:type n: int
:type roads: List[List[int]]
:rtype: int
"""
def inplace_counting_sort(nums, reverse=False): # Time: O(n)
count = [0]*(max(nums)+1)
for num in nums:
count[num] += 1
for i in xrange(1, len(count)):
count[i] += count[i-1]
for i in reversed(xrange(len(nums))): # inplace but unstable sort
while nums[i] >= 0:
count[nums[i]] -= 1
j = count[nums[i]]
nums[i], nums[j] = nums[j], ~nums[i]
for i in xrange(len(nums)):
nums[i] = ~nums[i] # restore values
if reverse: # unstable sort
nums.reverse()
degree = [0]*n
for a, b in roads:
degree[a] += 1
degree[b] += 1
inplace_counting_sort(degree)
return sum(i*x for i, x in enumerate(degree, 1))
# Time: O(nlogn)
# Space: O(1)
# greedy, sort
class Solution2(object):
def maximumImportance(self, n, roads):
"""
:type n: int
:type roads: List[List[int]]
:rtype: int
"""
degree = [0]*n
for a, b in roads:
degree[a] += 1
degree[b] += 1
degree.sort()
return sum(i*x for i, x in enumerate(degree, 1))