Medium
Maximum Sum of Three Numbers Divisible by Three — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
# sort, math
class Solution(object):
def maximumSum(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
def add(arr, x):
for i in xrange(len(arr)):
if x > arr[i]:
arr[i], x = x, arr[i]
if len(arr) != 3:
arr.append(x)
group = [[] for _ in xrange(3)]
for x in nums:
add(group[x%3], x)
result = 0
for g in group:
if len(g) == 3:
result = max(result, sum(g))
if group[0] and group[1] and group[2]:
result = max(result, group[0][0]+group[1][0]+group[2][0])
return result
# Time: O(nlogn)
# Space: O(n)
# sort, math
class Solution2(object):
def maximumSum(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
group = [[] for _ in xrange(3)]
for x in nums:
group[x%3].append(x)
result = 0
for g in group:
g.sort(reverse=True)
if len(g) >= 3:
result = max(result, sum(g[i] for i in xrange(3)))
if group[0] and group[1] and group[2]:
result = max(result, group[0][0]+group[1][0]+group[2][0])
return result