Medium
Maximum Sum Circular Subarray — Python
Full explanation · Time O(n) · Space O(1)
# Time: O(n)
# Space: O(1)
class Solution(object):
def maxSubarraySumCircular(self, A):
"""
:type A: List[int]
:rtype: int
"""
total, max_sum, cur_max, min_sum, cur_min = 0, -float("inf"), 0, float("inf"), 0
for a in A:
cur_max = max(cur_max+a, a)
max_sum = max(max_sum, cur_max)
cur_min = min(cur_min+a, a)
min_sum = min(min_sum, cur_min)
total += a
return max(max_sum, total-min_sum) if max_sum >= 0 else max_sum