Medium
Maximum Subtree of the Same Color — C++
Full explanation · Time O(n) · Space O(h)
// Time: O(n)
// Space: O(h)
// iterative dfs
class Solution {
public:
int maximumSubtreeSize(vector<vector<int>>& edges, vector<int>& colors) {
vector<vector<int>> adj(size(colors));
for (const auto& e : edges) {
adj[e[0]].emplace_back(e[1]);
adj[e[1]].emplace_back(e[0]);
}
const auto& iter_dfs = [&]() {
int result = 0;
using RET = int;
RET ret{1};
vector<tuple<int, int, int, int, shared_ptr<RET>, RET *>> stk = {{1, 0, -1, -1, nullptr, &ret}};
while (!empty(stk)) {
const auto [step, u, p, i, new_ret, ret] = stk.back(); stk.pop_back();
if (step == 1) {
stk.emplace_back(4, -1, -1, -1, nullptr, ret);
stk.emplace_back(2, u, p, 0, nullptr, ret);
} else if (step == 2) {
if (i == size(adj[u])) {
continue;
}
const auto& v = adj[u][i];
stk.emplace_back(2, u, p, i + 1, nullptr, ret);
if (v == p) {
continue;
}
const auto& new_ret = make_shared<RET>(1);
stk.emplace_back(3, u, p, i, new_ret, ret);
stk.emplace_back(1, v, u, -1, nullptr, new_ret.get());
} else if (step == 3) {
const auto& v = adj[u][i];
if (*ret == -1) {
continue;
}
if (*new_ret == -1 || colors[v] != colors[u]) {
*ret = -1;
continue;
}
*ret += *new_ret;
} else if (step == 4) {
result = max(result, *ret);
}
}
return result;
};
return iter_dfs();
}
};
// Time: O(n)
// Space: O(h)
// dfs
class Solution2 {
public:
int maximumSubtreeSize(vector<vector<int>>& edges, vector<int>& colors) {
vector<vector<int>> adj(size(colors));
for (const auto& e : edges) {
adj[e[0]].emplace_back(e[1]);
adj[e[1]].emplace_back(e[0]);
}
int result = 0;
const function<int (int, int)> dfs = [&](int u, int p) {
int cnt = 1;
for (const auto& v : adj[u]) {
if (v == p) {
continue;
}
const auto c = dfs(v, u);
if (cnt == -1) {
continue;
}
if (c == -1 || colors[v] != colors[u]) {
cnt = -1;
continue;
}
cnt += c;
}
result = max(result, cnt);
return cnt;
};
dfs(0, -1);
return result;
}
};