Hard
Maximum Subgraph Score in a Tree — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
# bfs, tree dp
class Solution(object):
def maxSubgraphScore(self, n, edges, good):
"""
:type n: int
:type edges: List[List[int]]
:type good: List[int]
:rtype: List[int]
"""
adj = [[] for _ in xrange(n)]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
parent = [-1]*n
q = [0]
for u in q:
for v in adj[u]:
if v == parent[u]:
continue
parent[v] = u
q.append(v)
dp = [1 if x else -1 for x in good]
for u in reversed(q):
if parent[u] == -1:
continue
dp[parent[u]] += max(dp[u], 0)
for u in q:
if parent[u] == -1:
continue
dp[u] += max(dp[parent[u]]-max(dp[u], 0), 0)
return dp