Hard
Maximum Strong Pair XOR II — C++
Full explanation · Time O(nlogr) · Space O(t)
// Time: O(nlogn + nlogr) = O(nlogr), r = max(nums)
// Space: O(t)
// bit manipulation, greedy, trie, sort, two pointers
class Solution {
private:
class Trie {
public:
Trie(int bit_length)
: bit_length_(bit_length)
, nodes_() {
new_node();
}
void update(int num, int d) {
int curr = 0;
for (int i = bit_length_ - 1; i >= 0; --i) {
int x = num >> i;
if (nodes_[curr][x & 1] == -1) {
nodes_[curr][x & 1] = new_node();
}
curr = nodes_[curr][x & 1];
cnts_[curr] += d;
}
}
int query(int num) {
int result = 0, curr = 0;
for (int i = bit_length_ - 1; i >= 0; --i) {
result <<= 1;
const int x = num >> i;
if (nodes_[curr][1 ^ (x & 1)] != -1 && cnts_[nodes_[curr][1 ^ (x & 1)]]) {
result |= 1;
curr = nodes_[curr][1 ^ (x & 1)];
} else {
curr = nodes_[curr][x & 1];
}
}
return result;
}
private:
int new_node() {
nodes_.push_back(array<int, 2>{-1, -1});
cnts_.emplace_back(0);
return size(nodes_) - 1;
}
const int bit_length_;
vector<array<int, 2>> nodes_;
vector<int> cnts_;
};
public:
int maximumStrongPairXor(vector<int>& nums) {
sort(begin(nums), end(nums));
Trie trie(bit_length(nums.back()));
int result = 0;
for (int i = 0, j = 0; i < size(nums); ++i) {
trie.update(nums[i], +1);
while (!(nums[i] <= 2 * nums[j])) {
trie.update(nums[j++], -1);
}
result = max(result, trie.query(nums[i]));
}
return result;
}
private:
int bit_length(int x) {
return (x ? std::__lg(x) : -1) + 1;
}
};
// Time: O(nlogr), r = max(nums)
// Space: O(t)
// bit manipulation, greedy, trie, dp
class Solution2 {
private:
class Trie {
public:
Trie(int bit_length)
: bit_length_(bit_length)
, nodes_() {
new_node();
}
void insert(int num) {
int curr = 0;
for (int i = bit_length_ - 1; i >= 0; --i) {
int x = num >> i;
if (nodes_[curr][x & 1] == -1) {
nodes_[curr][x & 1] = new_node();
}
curr = nodes_[curr][x & 1];
mins_[curr] = min(mins_[curr], num);
maxs_[curr] = max(maxs_[curr], num);
}
}
int query(int num) {
int result = 0, curr = 0;
for (int i = bit_length_ - 1; i >= 0; --i) {
result <<= 1;
const int x = num >> i;
const int y = (result | 1) ^ x;
assert(x != y);
if (nodes_[curr][y & 1] != -1 &&
((x > y && num <= 2 * maxs_[nodes_[curr][y & 1]]) ||
(x < y && mins_[nodes_[curr][y & 1]] <= 2 * num))) {
result |= 1;
curr = nodes_[curr][y & 1];
} else {
curr = nodes_[curr][(y & 1) ^ 1];
}
}
return result;
}
private:
int new_node() {
nodes_.push_back(array<int, 2>{-1, -1});
mins_.emplace_back(numeric_limits<int>::max());
maxs_.emplace_back(numeric_limits<int>::min());
return size(nodes_) - 1;
}
const int bit_length_;
vector<array<int, 2>> nodes_;
vector<int> mins_;
vector<int> maxs_;
};
public:
int maximumStrongPairXor(vector<int>& nums) {
Trie trie(bit_length(*max_element(cbegin(nums), cend(nums))));
int result = 0;
for (const auto& num : nums) {
trie.insert(num);
result = max(result, trie.query(num));
}
return result;
}
private:
int bit_length(int x) {
return (x ? std::__lg(x) : -1) + 1;
}
};
// Time: O(nlogr), r = max(nums)
// Space: O(n)
// bit manipulation, greedy, dp
class Solution3 {
public:
int maximumStrongPairXor(vector<int>& nums) {
int result = 0;
for (int i = bit_length(*max_element(cbegin(nums), cend(nums))) - 1; i >= 0; --i) {
unordered_map<int, int> prefix_min, prefix_max;
for (const auto& x : nums) {
const int y = x >> i;
if (!prefix_min.count(y)) {
prefix_min[y] = prefix_max[y] = x;
}
prefix_min[y] = min(prefix_min[y], x);
prefix_max[y] = max(prefix_max[y], x);
}
result <<= 1;
for (const auto& [x, _] : prefix_min) {
const int y = (result | 1) ^ x;
assert(x != y);
if (prefix_max.count(y) && prefix_min[max(x, y)] <= 2 * prefix_max[min(x, y)]) {
result |= 1;
break;
}
}
}
return result;
}
private:
int bit_length(int x) {
return (x ? std::__lg(x) : -1) + 1;
}
};