Medium
Maximum Product Subarray — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int maxProduct(vector<int>& nums) {
int result = numeric_limits<int>::min();
int curr_min = 1, curr_max = 1;
for (const auto& num : nums) {
tie(curr_min, curr_max) = pair(min({num, curr_min * num, curr_max * num}),
max({num, curr_min * num, curr_max * num}));
result = max(result, curr_max);
}
return result;
}
};