Easy
Maximum Product of Three Numbers — C++
Full explanation · Time O(n) · Space O(1)
// Time: O(n)
// Space: O(1)
class Solution {
public:
int maximumProduct(vector<int>& nums) {
auto min1 = numeric_limits<int>::max();
auto min2 = numeric_limits<int>::max();
auto max1 = numeric_limits<int>::min();
auto max2 = numeric_limits<int>::min();
auto max3 = numeric_limits<int>::min();
for (const auto& n: nums) {
if (n <= min1) {
min2 = min1;
min1 = n;
} else if (n <= min2) {
min2 = n;
}
if (n >= max1) {
max3 = max2;
max2 = max1;
max1 = n;
} else if (n >= max2) {
max3 = max2;
max2 = n;
} else if (n >= max3) {
max3 = n;
}
}
return max(min1 * min2 * max1, max1 * max2 * max3);
}
};