Hard
Maximum Points Tourist Can Earn — C++
Full explanation · Time O(k * n^2) · Space O(n)
// Time: O(k * n^2)
// Space: O(n)
// dp
class Solution {
public:
int maxScore(int n, int k, vector<vector<int>>& stayScore, vector<vector<int>>& travelScore) {
vector<int> dp(n);
for (int i = 0; i < k; ++i) {
vector<int> new_dp(n);
for (int u = 0; u < n; ++u) {
new_dp[u] = dp[u] + stayScore[i][u];
}
for (int u = 0; u < n; ++u) {
for (int v = 0; v < n; ++v) {
new_dp[u] = max(new_dp[u], dp[v] + travelScore[v][u]);
}
}
dp = move(new_dp);
}
return ranges::max(dp);
}
};