Maximum Performance of a Team — C++

// Time:  O(nlogn)
// Space: O(n)

class Solution {
public:
    int maxPerformance(int n, vector<int>& speed, vector<int>& efficiency, int k) {
        static const int MOD = 1e9 + 7;
        uint64_t result = 0, s_sum = 0;
        vector<pair<int, int>> engineers;
        for (int i = 0; i < speed.size(); ++i) {
            engineers.emplace_back(efficiency[i], speed[i]);
        }
        sort(engineers.begin(), engineers.end(), greater<pair<int, int>>());
        priority_queue<int, vector<int>, greater<int>> min_heap;
        for (const auto& [e, s] : engineers) {
            s_sum += s;
            min_heap.emplace(s);
            if (min_heap.size() > k) {
                s_sum -= min_heap.top(); min_heap.pop();
            }
            result = max(result, s_sum * e);
        }
        return result % MOD;
    }
};