Medium
Maximum OR — C++
Full explanation · Time O(n) · Space O(n)
// Time: O(n)
// Space: O(n)
// prefix sum, greedy
class Solution {
public:
long long maximumOr(vector<int>& nums, int k) {
vector<int> right(size(nums) + 1);
for (int i = size(nums) - 1; i >= 0; --i) {
right[i] = right[i + 1] | nums[i];
}
int64_t result = 0;
int left = 0;
for (int i = 0; i < size(nums); ++i) {
result = max(result, left | (static_cast<int64_t>(nums[i]) << k) | right[i + 1]);
left |= nums[i];
}
return result;
}
};