Medium
Maximum Number of Removable Characters — C++
Full explanation · Time O(rlogn) · Space O(r)
// Time: O(rlogn)
// Space: O(r)
// if r = O(1), this is better
class Solution {
public:
int maximumRemovals(string s, string p, vector<int>& removable) {
int left = 0, right = size(removable);
while (left <= right) {
int mid = left + (right - left) / 2;
if (!check(s, p, removable, mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return right;
}
private:
bool check(const string& s, const string& p, const vector<int>& removable, int x) {
unordered_set<int> lookup;
for (int i = 0; i < x; ++i) {
lookup.emplace(removable[i]);
}
int j = 0;
for (int i = 0; i < size(s); ++i) {
if (lookup.count(i) || s[i] != p[j]) {
continue;
}
if (++j == size(p)) {
return true;
}
}
return false;
}
};
// Time: O(rlogn)
// Space: O(n)
// if r = O(n), this is better
class Solution2 {
public:
int maximumRemovals(string s, string p, vector<int>& removable) {
vector<int> lookup(size(s), numeric_limits<int>::max());
for (int i = 0; i < size(removable); ++i) {
lookup[removable[i]] = i + 1;
}
int left = 0, right = size(removable);
while (left <= right) {
int mid = left + (right - left) / 2;
if (!check(s, p, lookup, mid)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return right;
}
private:
bool check(const string& s, const string& p, const vector<int>& lookup, int x) {
int j = 0;
for (int i = 0; i < size(s); ++i) {
if (lookup[i] <= x || s[i] != p[j]) {
continue;
}
if (++j == size(p)) {
return true;
}
}
return false;
}
};