Medium
Maximum Number of Operations With the Same Score II — Python
Full explanation · Time O(n^2) · Space O(n^2)
# Time: O(n^2)
# Space: O(n^2)
# memoization
class Solution(object):
def maxOperations(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
def memoization(left, right, target, lookup):
if not right-left+1 >= 2:
return 0
if lookup[left][right] == -1:
lookup[left][right] = max(1+memoization(left+2, right-0, target, lookup) if nums[left]+nums[left+1] == target else 0,
1+memoization(left+1, right-1, target, lookup) if nums[left]+nums[right] == target else 0,
1+memoization(left+0, right-2, target, lookup) if nums[right-1]+nums[right] == target else 0)
return lookup[left][right]
return max(memoization(0, len(nums)-1, target, [[-1]*(len(nums)) for _ in xrange(len(nums))]) for target in {nums[0]+nums[1], nums[0]+nums[-1], nums[-2]+nums[-1]})