Medium
Maximum Number of Non-Overlapping Subarrays With Sum Equals Target — Python
Full explanation · Time O(n) · Space O(n)
# Time: O(n)
# Space: O(n)
class Solution(object):
def maxNonOverlapping(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
lookup = {0:-1}
result, accu, right = 0, 0, -1
for i, num in enumerate(nums):
accu += num
if accu-target in lookup and lookup[accu-target] >= right:
right = i
result += 1 # greedy
lookup[accu] = i
return result